Question

A and b are constants what is one solution of (x+a)(x-b)=0

Answer 1

hiii...

(x+a)(x-b)=0

x²-bx+ax-ab =0

x²= bx-ax+ab

x²= x(b-a)+ab

x²/x= (b-a)+ab

x= (b-a)+ab

hope it gelps u..

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