A and B are equally good tennis players. Which of the following two events is more probable. (i) A beats B exactly in 3 games out of 4. (ii) S beats B exactly in 5 games out of 8?
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Hey there!
Let's look at the both events and find which as 50% probability.
Probability of event 1
= 3/4*100
=75%
Probability of event2
= 5/8*100
= 0.5 +0.125 *100
= 0.625 *100
= 62.5
So 62.5 is nearer to 50%.
So, A beats B exactly in 5 games out of 8
hope helped!
Let's look at the both events and find which as 50% probability.
Probability of event 1
= 3/4*100
=75%
Probability of event2
= 5/8*100
= 0.5 +0.125 *100
= 0.625 *100
= 62.5
So 62.5 is nearer to 50%.
So, A beats B exactly in 5 games out of 8
hope helped!
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