A and B are equally good tennis players which of the following two events is more probable (1) A beats B exactly in 3 games out of 4 (2) A beats B exactly in 5 games out of 8
Expecting Good answer !
Answers
Answered by
1
A beats B in 3 games of 4. --> Case (1)
Percentage of wining of A = 75%
Percentage of Winning of B =25%
A beats B in 5 games of 8 ----> Case (2)
Percentage of wining of A = 62.5%
Percentage of Winning of B =37.5%
As in Case (2) Winning of both persons are nearly equal than Case(1).
If A,B are equally good tennis players, then A beats B exactly in 5 out of 8 games is most probable.
Percentage of wining of A = 75%
Percentage of Winning of B =25%
A beats B in 5 games of 8 ----> Case (2)
Percentage of wining of A = 62.5%
Percentage of Winning of B =37.5%
As in Case (2) Winning of both persons are nearly equal than Case(1).
If A,B are equally good tennis players, then A beats B exactly in 5 out of 8 games is most probable.
Similar questions