A and B are events such that () = 0.42, () = 0.48 and (and) = 0.16
Determine :
(i) (not)
(ii) (not)
(iii) (or)
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It is given that P(A)=0.42,P(B)=0.48,P(AandB)=0.16
(i) P(notA)=1−P(A)=1−0.42=0.58
(ii) P(notB)=1−P(B)=1−0.48=0.52
(iii) We know that P(AorB)=P(A)+P(B)−P(AandB)
∴P(AorB)=0.42+0.48−0.16=0.74
Step-by-step explanation:
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