Math, asked by nikki25, 1 year ago

A and B are friends. A is elder to B by 5 years. B's sister C is the half the age of B while A's father D is 8 years older than twice the age of B. if the present age of D is 48 years.find the present ages of A,B and C

nikki25: sir plz give me the answer i really need it

Anonymous: your answer miss nikki with description

Answers

Answered by Anonymous

170

Let the age of B be x.
so,
the age of a = 5 + x
the age of b = x
the age of c = x/2
the age of d = 8+2x
If, d=48 years then, 48=8+2x =>2x=40 => x=20 years

The present population of A = (20 + 5) years = 25 years
The present population of B = 20 years
The present population of C = (20/2) years = 10 years.

Anonymous: say!!!

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Anonymous: miss nikki

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Anonymous: so

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Answered by mahesh13576

Answer

Let the age of B be x.

Let the age of B be x.So,

Let the age of B be x.So,the age of a = 5 + x

Let the age of B be x.So,the age of a = 5 + xthe age of b = x the age of c = x/2

Let the age of B be x.So,the age of a = 5 + xthe age of b = x the age of c = x/2the age of d = 8+2x

Let the age of B be x.So,the age of a = 5 + xthe age of b = x the age of c = x/2the age of d = 8+2xIf, d=48 years then, 48-8+2x =>2x=40 => x=20 years

Let the age of B be x.So,the age of a = 5 + xthe age of b = x the age of c = x/2the age of d = 8+2xIf, d=48 years then, 48-8+2x =>2x=40 => x=20 yearsThe present population of A = (20 + 5)

Let the age of B be x.So,the age of a = 5 + xthe age of b = x the age of c = x/2the age of d = 8+2xIf, d=48 years then, 48-8+2x =>2x=40 => x=20 yearsThe present population of A = (20 + 5)years = 25 years The present population of B = 20 years The present population of C = (20/2)

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