A and B are friends and A is older to B by 2 years A's father D is twice as old as A nd B is twice as old as his sister C if the ages of D and C differ by 40 years find the age of A
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Answer: A will be 29 years old
Step-by-step explanation:
let A be x
B will be x-2
D will be 2x
C will be B/2 = (x-2)/2
we know that,
D-C = 40
2x-{(x-2)/2} = 40
2x-(x-2)/2 = 40
(4x-x+2)/2 = 40
3x+2 = 80
3x = 78
x = 29
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