Math, asked by vinayhariprasad, 10 months ago

A and B are friends and A is older to B by 2 years A's father D is twice as old as A nd B is twice as old as his sister C if the ages of D and C differ by 40 years find the age of A

Answers

Answered by Anonymous
0

Answer: A will be 29 years old

Step-by-step explanation:

let A be x

B will be x-2

D will be 2x

C will be B/2 = (x-2)/2

we know that,

D-C = 40

2x-{(x-2)/2} = 40

2x-(x-2)/2 = 40

(4x-x+2)/2 = 40

3x+2 = 80

3x = 78

x = 29

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