Question

A and B are friends and their ages differ by 2 years as father is twice as old as A and B is twice as old as his sister C. the age of D and C are differ by 40 years find the ages of A and B

Answer 1

Answer:

A=26 years

B=28 years

Step-by-step explanation:

let the age of A = x

age of B = x+2

since, A's father D is twice as old as A

So, age of D = 2×x = 2x

and since B is twice as old as his sister

So, age of C = age of B / 2 = (x+2)/2

according to the question,

The ages of D and C differ by 40yrs.

it means,

age of D - age of C = 40

=> 2x - [(x+2)/2] = 40

=> 2x - (x+2)/2 = 40

=> 4x/2 - (x+2)/2 = 40

=> (4x - x + 2)/2 = 40

=> 3x+2/2 = 40

=> 3x + 2 = 40 × 2

=> 3x = 80 - 2

=> x = 78/3

= 26

So, age of A = x = 26yrs

age of B = x + 2 = 26 + 2 = 28yrs

Hope this helps

THANK YOU

sumanth s