Math, asked by doll1893, 1 year ago

A and B are friends. They decide to meet between 1 PM and 2 PM on a given
day. There is a conditions that whoever arrives first will not wait for the other for
more than 15 minutes. The probability that they will meet on that days is
(A) 1 4/ (B) 1 16 /
(C) 7 16 / (D) 9 16

Answers

Answered by Anonymous
5
the probability is 7/16
Answered by mkrishnan
4

Answer:

Step-by-step explanation:

let A  arrives first   B  comes second

probability for B to come within 15 minutes =15/60 =1/4

let B  arrives first   A  comes second

probability for A to come within 15 minutes =15/60 =1/4

OUT OF THESE TWO CASES

only one is possible  either A or B  come first    

so  probability for A come first =1/2

     probability for B come first =1/2

SO ANSWER IS    1/2x1/4 +1/2x1/4 =1/8+1/8 =1/4

Similar questions