A and B are friends. They decide to meet between 1 PM and 2 PM on a given
day. There is a conditions that whoever arrives first will not wait for the other for
more than 15 minutes. The probability that they will meet on that days is
(A) 1 4/ (B) 1 16 /
(C) 7 16 / (D) 9 16
Answers
Answered by
5
the probability is 7/16
Answered by
4
Answer:
Step-by-step explanation:
let A arrives first B comes second
probability for B to come within 15 minutes =15/60 =1/4
let B arrives first A comes second
probability for A to come within 15 minutes =15/60 =1/4
OUT OF THESE TWO CASES
only one is possible either A or B come first
so probability for A come first =1/2
probability for B come first =1/2
SO ANSWER IS 1/2x1/4 +1/2x1/4 =1/8+1/8 =1/4
Similar questions