Question

A and B are mutually exclusive such that P(A)=0.4,P(AUB)=0.7,then P(B)

Answer 1

P(A)=0.4, P(AUB)=0.7

A and B are mutually exclusive its means P(AnB) =0

P(AUB) = P(A) + P(B) - P(AnB)

0.7 = 0.4 + P(B) - 0

P(B) = 0.7 - 0.4 = 0.3