A and B are points on a line that has the slope –3. The abscissa of B exceeds the abscissa of A by 2. State the relationship of the ordinate of B to the ordinate of A.
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Let A be the point . (a,b)
Then B must be (a+2, b+c)
We are trying to find the value of c here and we know that the slope of line through A and B is - 3.
So with the slope of -3 we will get this:
b - (b+c)/ a - (a+2) = -3
eiπ + 1 = 0
If there is any confusion please leave a comment below.
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