Question

'a' and 'b' are positive integers less than 6 How many distinct values can (2a + 3b) take?
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Answer 1

Step-by-step explanation:

basically we need to understand that is expecting from us to separate a cube from the rest of the number

so we should be able to write the left part of the equation in the form that is represented on the right side of the equation

Let,

and

and

So we have to represent

Total factors of = (1+1)*(1+1)*(2+1) = 12

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Answer 2

Answer: a=0 and b=1 OR a=1 and b=0

Step-by-step explanation:

• To this expression we need to put such values of a and b so that the result is always less than 6.
• When we put a=0 and b=1 we get 3 which is possible.
• When we put a=1 and b=0 then we get 2 which is possible.
• If we put a=1 and b=2 then we get 8 which is not satisfying the condition.
• So, the only possible values of a and b is 0 and 1.
• Hence, the possible values are 0 and 1 interchangeably put in the equation.

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