Question

A and B are the two alloys of copper and brass prepared by mixing metals in the proportion of 7:2

and 7:11 respectively. If the equal quantities of two alloys are melted to form a third alloy called C,

then the proportion of copper and brass in C will be​

Answer 1

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Answer 2

Answer : 7 : 5

Alloy A → Brass : Copper = 7a : 2a

Alloy B → Brass : Copper = 7b : 11b

Same amount of alloy A and B are used.

9a = 18b

a = 2b

We have a = 2b.

Alloy C → ( 7a + 7b ) : ( 2a + 11b )

Now substitute a = 2b.

( 7a + 7b ) : ( 2a + 11b ) = 21b : 15b

∴ 21 : 15 = 7 : 5