A and b are the two radioactive elements. The mixture of these elements show a total activity of 1200 disintegrations/minute. The half-life of a is 1 day and that of b is 2 days . What will be the total activity after 4 days? Given, the initial number of atoms in a and b are equal
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Hey dear,
● Answer- 150 dis/min
● Solution-
Half lives for A = 4/1 = 4 lives
Half lives for B = 4/2 = 2 lives
Average half life = (4+2)/2 = 3 half lives
No of atoms remaining after 4 days-
x = x0 / 2^3
x = 1200 / 8
x = 150 dis/min
Disintegration after 4 days is 150 dis/min.
Hope this is helpful...
● Answer- 150 dis/min
● Solution-
Half lives for A = 4/1 = 4 lives
Half lives for B = 4/2 = 2 lives
Average half life = (4+2)/2 = 3 half lives
No of atoms remaining after 4 days-
x = x0 / 2^3
x = 1200 / 8
x = 150 dis/min
Disintegration after 4 days is 150 dis/min.
Hope this is helpful...
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Answer:
150 is the the the answer of this question
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