Question

A and B are two candidates seeking admission in a college. The probability that A is selected is 0.7 and the probability that exactly one of them is selected is 0.6 . Find the probability that B is selected.

Answer 1

1 = 0.7+p(b)-0.6
p(b)= 1-0.1
= 0.9

Answer 2

Answer:

The probability that B is selected = 0.25

Step-by-step explanation:

P(A) = 0.7

Let P(B) = p

the probability that exactly one of them is selected is 0.6

⇒ A is selected and B is not selected OR B is selected and B is not selected = 0.6

⇒ P(A)[1 - p] + p[1 - P(A)] = 0.6

⇒ 0.7 - 0.7p + p - 0.7p = 0.6

⇒ 0.4p = 0.1

⇒ p = 0.25

⇒ P(B) = 0.25

Therefore, The probability that B is selected = 0.25