Question

A and B are two different numbers selected from the first 40 natural numbers, then the largest value of A×B/A-B is

​

Answer 1

Let we can choose the last two numbers from the list of first forty  natural no's,

i.e A=40, B=39

So the largest value of A*B/A-B= 40*39/40-39

= 1560/1= 1560.....