Question

A and B are two equipotential surfaces as
shown in the figure. A charge of 2 uc is shot
from origin with 10^2m/s. Find work done by the
field on the charge to cross the field. If field
extends upto 20 cm in Yaxis. [Given V1-V2=10^3V]
​

Answer 1

Given that,

Charge = 2 μC

Speed = 10² m/s

Change in potential $(V_{1}-V_{2})= 10^{3}\ V$

We need to calculate the work done

Using formula of work done

$W=q(\Delta V)$

Where, q = charge

$\Delta V$ = change in potential

Put the value into the formula

$W=2\times10^{-6}\times(10^{3})$

$W=2\times10^{-3}\ J$

Hence, The work done is $2\times10^{-3}\ J$