Question

A and B are two events such that P(A) = 0.4 and P(A ∩ B) = 0.2 Then P(A ∩ B) is equal to

Answer 1

Answer:

0.4

explanation:

P(A ∩ B) = P(A – (A ∩ B))

= P(A) – P(A ∩ B)

= 0.6 – 0.2 Using P(A) = 1 – P(A)

= 0.4

Answer 2

P(A ∩ B') = 0.2

Given :

A and B are two events such that P(A) = 0.4 and P(A ∩ B) = 0.2

To find :

The value of P(A ∩ B')

Formula :

P(A ∩ B') = P(A) - P(A ∩ B)

Where P(E) is probability of the event E

Solution :

Step 1 of 2 :

Write down the probability

Here it is given that A and B are two events such that P(A) = 0.4 and P(A ∩ B) = 0.2

Step 2 of 2 :

Find the value of P(A ∩ B')

P(A ∩ B')

= P(A) - P(A ∩ B)

= 0.4 - 0.2

= 0.2

Correct question : A and B are two events such that P(A) = 0.4 and P(A ∩ B) = 0.2 Then P(A ∩ B') is equal to

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