Question

A and B are two events such that P(A)=0.4; P(B)=3.0 andP(A U B)=0.6 then find P(B

Answer 1

Answer:

Step-by-step explanation:

P(AuB)= p(A) + p(B) - p(AnB)

Since P(A) and P(B) are independent, the intersection is the product of their individual probabilities (p(A)*p(B)).

We then have P(AuB) =0.3 + 0.4 - 0.3*0.4= 0.58

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