A and b are two faulty clocks a loses 10 minutes for every hour and gains 10 minutes for every hour what is time shown by a a when time shoen by b is 7 p.m. on the same day
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because b is loses its time against the first watch
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Answer:
Step-by-step explanation:
The time difference between two clock is 20 mins/hour.
which means after two hours, the diff will be 40 mins.
and so after 7 hours the difference will be 7 x 20 = 140mins.
So b will be 140 mins ahead of a, after 7 hours.
so a will show =7 - 140 mins = 4:40pm.
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