A and B are two fixed points. the locus of P such that in ∆PAB,sinB/sinAis a constant
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0
Answer:
Let A(x
1
,y
1
) and B(x
2
,y
2
) be two fixed points and P(h,k) be a variable point such that
∠APB=
2
π
Then, slope of AP× slope of BP=−1
⇒
h−x
1
k−y
1
×
h−x
2
k−y
2
=−1
⇒(h−x
1
)(h−x
2
)+(k−y
1
)(k−y
2
)=0
Hence, locus of (h,k) is
(x−x
1
)(x−x
2
)+(y−y
1
)(y−y
2
)=0
which is a circle having AB as diameter.
Answered by
0
Answer:
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Step-by-step explanation:
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