Question

A and B are two hollow metal spheres of radii 50 cm and 1 m carrying charges 0.6 micro coulomb and 1 micro coulomb respectively. They are connected externally by a conducting wire. Now the charge flows from
a) A to B till the charges become equal.
b) B to A till the charges become equal.
c) A to B till potentials become equal
d) B to A till potentials become equal11. 11. 10. Point
charges +q, +q, and - q are placed at the corners A, B and C respectively of an equilateral triangle ABC. The resultant force on - q placed at C acts:​

Answer 1

Answer:

Correct option is

C

Explanation:

A to B till the potentials become equal

The potential of a sphere of radius r carrying a charge q is rkq

.

Hence potential of first sphere=V

A = 0.5m k(0.6μC)

Potential of second sphere=V

B = 1m k(1μC)

⟹V A >V B

Hence charge flows from A to B till the potentials become equal.

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Answer 2

Answer:

The potential of a sphere of radius r carrying a charge q is

r kq

.

Hence potential of first sphere=VA = 0.5mk(0.6μC)

Potential of second sphere=VB = 1mk(1μC)

⟹V A >V B

Hence charge flows from A to B till the potentials become equal.