Question

A and B are two identical vessels. A contains 15 g ethane at 1 atm and 298 K. The vessel B contains 75 g of gas 'X' at same temperature and pressure. Calculate the vapour density of X .​

Answer 1

Answer:

Explanation:

pv =nrt here p, v and t are constant therefore n is constant now the ratio of given mass and molecular mass also will be constant

therfore

15/30 = 75/molecular mass of gas

which gives the unknown molecular mass as 150

now we know vapur density is molecular mass /2

therefore 150/2 or 75

and 75 is the answer

Answer 2

Answer:

Heya.....

Here's ur answer :

Given: mass of ethane = W1 = 15 g

mass of X = W2 = 75 g

Mol. Wt of ethane = M1 =30 g/mol

Mol. Wt of X = M2 = ?

At constant temperature and pressure, and volume,

but, no. of moles are not constant.

Using Avagadro's Law - (Volume -mole relationship)

=> V1/n1 = V2/n2

but, v1 = v2 = v

=> v/n1 = v/n2

=> n1 = n2

=> W1/M1 = W2/M2

=> 15/30 = 75/M2

=> M2 = 75*2

=> M2 = 150 g/mol

we have,

Vapour density = Molecular Wt. /2

.°. Vapour density of 'X' = 150/2

=> Vapour density of 'X' = 75 ,,

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✨Hope it helps!!!.... ✌