Question

A and B are two mutually exclusive events if P(A)=0.5 and P(B)=0.6 find P(AUB)

Answer 1

since they are mutually exclusive P(AUB)=P(A)+P(B) therefore P(AUB)=1.1

Answer 2

Given,

P(A) = 0.5

P(B) = 0.6

To find,

P(AUB)

Solution,

The value of P(AUB) is 1.1

We can simply solve the mathematical problem by the following procedure.

It is given that A and B are mutually exclusive.

Thus,

P(A∩B) = 0

Now,

We know that,

∴ P(A∪B) = P(A) + P(B) - P(A∩B)

⇒ P(AUB) = 0.5 + 0.6 - 0

                = 1.1

As a result, the value of P(AUB) is 1.1