Question

A and B are two natural numbers such that lcm(a,b) =144 and hcf = 16 then find a and b​

Answer 1

Answer:

a=16 ; b=144

Explanation:

as the lcm is 144 and hcf is 16, let a=16(x) and b=16(y) such that x and y are co-prime as hcf of 16x and 16y is 16.

so lcm of 16x and 16y is 144

lcm of x and y is 144/16 =9 and as hcf=1, x*y=lcm of x and y

x.       y.

1.       9

3       3

as 3 and 3 are not co-prime, x and y are 1 and 9

so a=16*1=16

b=16*9=144

hope it helps!