Physics, asked by rallapallisavith, 5 months ago

'A' and 'B' are two pegs separated by 13 cm. A body of 169 kgwt is suspended by thread of 17 cm connecting A & B, such that the two segments of strings are perpendicular. Then tensions in shorter and longer parts of string having are:

Answers

Answered by ghijhkknn
1

Explanation:

two pegs separated by 13 cm. A body of 169 kgwt is suspended by thread of 17 cm connecting A & B, such that the two segments of strings are perpendicular. Then tensions in shorter and longer parts of string

Answered by Yamini2110
3

Answer:

156kgwt , 65kgwt

Explanation:

169g/Sin90°= T1/Sin(90+θ)=T2sin(180−θ)

T1 =169g×cosθ =169*12/13 =156kgwt

T2=169g× 5/13 =65kgwt

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