A and B are two points 10 m apart. One body moves from A towards B at a constant velocity of 1.5m/s. At the same time another body starts from rest at B and move towards A with constant acceleration of 0.2m/s^2. They will meet at a point whose distance from A is?
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Step-by-step explanation:
Distance traveled by car A=SA
Distance traveled by car B=SB
According to formula S=ut+21at2
SA=0t+21×2t2
SB=10t+21×0t2
Car A will overtake car B when
SA=SB+100
Putting the value SA and SB
+2=10t+100
+2−10t−100=0
After solving for t, we get
t=16.18sec possible
t=−6.10sec not possible
Hope This will help you
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