Question

A and B are two points on a circle with center O and C lies outside the circle on ray AB ray. if the AB = 24 cm , BC=28cm,CA=15 cm then OC =​

Answer 1

Answer:

Step-by-step explanation:

Reckon it's (a) because:

If T is the point on the circle where the tangent from C touches, then:

CT^2 = CA*CB = 52*28

OC = OA = 15

OC^2 = CT^2 + OT^2 = 52*28 + 15*15

Therefore OC = Sqrt(52*28 + 15*15)

Answer 2

Step-by-step explanation:

your question seems to be wrong i think

it is written that c is outside the the circle but it is also written it is on AB ray so the question seems to be wrong I think

repost the question with a diagram if you can