.A and B are two sets such that n(A-B) = 32 + x, n(B-A) = 5x and n(ANB) = x. Illustratethe information by means of a Venn diagram. Given that n(A) = n(B), calculate thevalue of x.
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Step-by-step explanation
given:
n(A-B)=32+x
n(B-A)= 5x
n(A) = n(B)
n(A)= n(A-B) + n(AnB) (formula)
n(A) = 32+X+X
n(A) = 32+X,
n(B)= n(B-A)+n(AnB) (formula)
n(B) = 5X+X
n(B) = 6X.
n(A)=n(B) (given)
32+2X= 6X
32+2X-6X=0
32-4X=0
-4X=-32
X=32/4
X=8
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