a and b are two single digit natural number such that 0.abab..*n is an integer value for all values of a and b . what is the least three digit number that n can assume
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The fraction a/b is equals the repeating decimal 0.ababab. If a and b are single-digit positive integers, what is the value of a + b.
The repeating decimal 0.232323… is equal to 2399, and 0.373737… equals 3799, etc. In general, the repeating decimal 0.abab… is equal to 10a+b99. If this is also equal to ab, we get the equation,
ab=10a+b99
Solving this for a,
a=b299−10b,
which has single-digit positive integer solution a=b=9. Indeed,
9/9=0.9999…
so the answer to the question is a+b=18.
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thanks mama and papa you are interested in one NB
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