Question

A and B are two stations separated by a distance of 287km. At 7am two trains X and Y started moving from A and B towards B and A respectively. They both meet at 10:30am. If the speed of the train X is 6 kmph more than that of the train Y, then what is the speed of Y in kmph? 1. 44 2.36 3.54 4.38 5.45

Answer 1

The speed of Train Y is option 4, 38 kmph. The calculation is as given below.

If D is the distance between stations A and B, then D = 287km, since the distance between A and B is 287km.

Let the speeds of the train be x and y kmph respectively.

Then, x = y+6, since the speed of train X is 6 more than the speed of train Y.

The trains start at 7AM and meet at 10:30AM. In 3.5 hours, the distance traveled by the trains can be calculated as given below. For calculation purposes, we consider station A as the reference station.

Distance traveled by train X in 3.5 hours, traveling at x kmph = 3.5x
= 3.5 (y+6)
= 3.5y + 21

Distance traveled by train Y in 3.5 hours, traveling at y kmph = 3.5y.

But, since we have taken station A as the reference point,

3.5y = 287 - 3.5x

or 3.5y = 287 - 3.5y-21

or 7y = 287-21 = 266.

Therefore y = 266/7 = 38kmph.

Therefore, the speed of train Y is 38kmph and that of train X is 38+6 = 44kmph.