Question

A and B are two towers.the height of A is 20% less than the height of B.how much per cent is B's height more than that of A

Answer 1

please mark it as a brainliest answer

Answer 2

Answer:

The height of B is 25% more than A.

Step-by-step explanation:

It is given that the height of A is 20% less than the height of B.

Let the height of b is x. So, the height of A is

$A=x-\frac{20}{100}\times x=x-0.2x=0.8x$

We have to find by how much per cent is B's height more than that of A.

$\%=\frac{\text{Height of B-Height of A}}{\text{Height of A}}\times 100$

$\%=\frac{x-0.8x}{0.8x}\times 100$

$\%=\frac{0.2x}{0.8x}\times 100$

$\%=\frac{1}{4}\times 100$

$\%=25$

Therefore the height of B is 25% more than A.