Question

A and B are two towers . the height of tower A is 20% less than of B. how much per cent is B's height more than that of A?

Answer 1

Given that,

A and B are two towers. the height of tower A is 20% less than B.

To find,

How much percent is B's height more than that of A?

Solution,

Let x is the height of tower B. So, tower A's height is:

$A=x-20\%x\\\\A=0.8x$

Percent change is given by :

$\%=\dfrac{\text{Height of B-Height of A}}{\text{Height of A}}\times 100\%=\dfrac{x-0.8x}{0.8x}\times 100\\\\\%=\dfrac{0.2x}{0.8x}\times 100\\\\\%=\dfrac{1}{4}\times 100\\\\\%=25\%$

So, B's height is 25% more than that of A's height.