A and b are two unit vectors such that a + b is also a unit vector find angle between them
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Answered by
14
Answer:
120°
Step-by-step explanation:
Let θ be the angle between a and b, with 0° ≤ θ ≤ 180°.
|a+b| = 1
=> ( a + b ) · ( a + b ) = 1
=> a·a + b·b + 2a·b = 1
=> |a|² + |b|² + 2a·b = 1
=> 1 + 1 + 2a·b = 1 [ since a and b are unit vectors ]
=> 2a·b = -1
=> a·b = -1/2
=> |a| |b| cos θ = -1/2
=> cos θ = -1/2 [ since a and b are unit vectors ]
=> θ = 120°
Answered by
6
|a|=1 |b|=1 |a+b|=1
so, |a+b|=√{|a|² + |b|² +2|a||b|cos∆}
where ∆= angle between two vectors
take a square at both side
|a+b|² = |a|² + |b|² +2|a||b|cos∆
now put the value
1=1+1+2(cos∆)
-1=2(cos∆)
cos∆=-1/2
∆=π-π/3
∆=2π/3
∆=120°
thanks
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