Math, asked by Pranu5102, 10 months ago

A and B are two variable points on x, y axes respec- .
tively such that OA+OB=c. The locus of the foot of
the perpendicular from origin on this line AB is
1) x² + y2 = cxy 2) x² + y² = 2cxy
3) (x + y)(x2 + y2) = cxy 4) (x + y) (x² + y2) = 2cxy​

Answers

Answered by sainiazad23
0

Answer:

Correct option is

so you cqn choose my option thanks

A

(x2+y2)(x−y)=cxy

LettheequationoflineABbemx+axintercept=m−aabd,yintercept−aGiventhata+∣∣∣∣∣m−a∣∣∣∣∣=c

Letthefootofperpendicularbe(h,k)∴m+1cm=1−kn−ncn=h−kchk=mn+ak=k−h2+h−kch

Step-by-step explanation:

Correct option is

A

(x2+y2)(x−y)=cxy

LettheequationoflineABbemx+axintercept=m−aabd,yintercept−aGiventhata+∣∣∣∣∣m−a∣∣∣∣∣=c

Letthefootofperpendicularbe(h,k)∴m+1cm=1−kn−ncn=h−kchk=mn+ak=k−h2+h−kch

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