Question

a and b are two vectors given by A=2i+3j and B=i+j. The magnitude of the component of A along B is

Answer 1

heya friend!!☺☺
_____________________________________

here's your answer!!☺☺

The component of the vector A along B geometrically is:
Bcos(theta) = (A.B/|B|).(Bcap)
=5/(2)½ (i + j)

______________________________________

hope it helps you!!☺☺

Answer 2

Answer:

_____________________________________

⇒ The component of the vector A along B geometrically is:

⇒ Bcos(theta) = (A.B/|B|).(Bcap)

⇒ =5/(2)½ (i + j)

______________________________________