A and B are two wires. The radius of A is twice that of B. They are stretched by the same load. Then the stress on B is(a) equal to that on A(b) four times that on A(c) two times that on A(d) half that on A
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The stress on B is four times that on A.
Option (B) is correct.
Explanation:
rA = 2rB ---- (1)
Stress = F /A
Stress ∝ 1 / r^2
Stress A / stress B = r^2B / r^2 A
Stress of B = r^2B / r^2 A x Stress of A
Stress of B =(2rB)^2 / r^2B x Stress of A ----- From equation (1)
Stress of B = 4r^2B / r^2b x Stress of A
Stress on B = 4 . Stress on A
Thus the stress on B is four times that on A.
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Calculate the value of stress in a wire of steel having radius of 2 mm when 10 KN of force acts on it.?
https://brainly.in/question/9109721
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Answer:
4 times that of A
Explanation:
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