Math, asked by yurwish, 6 months ago

A and B are zeroes of the quadratic polynomial

f(x) = x2 – 6x + y. Find the value of ‘y’ if 3a + 2b = 20.

2marker​

Answers

Answered by anjalii5
1

Answer:

Pls check the image with explanations

Step-by-step explanation:

Attachments:
Answered by Anonymous
2

Answer:

Thus y = 8 or -72

Step-by-step explanation:

f(x) = x² – 6x + y

A and B are zeros of f(x)

so F(A)=0 and f(B)=0

A²-6A+y=0............(1)

and

B²-6B+y=0..............(2)

on subtration we get

A²-B²-6(A-B)=0

(A-B)( A+B-6)=0

A=B or A+B+6

also 3A+2B=20

3A+2A=20

A=4,B=4

From(1) 16-24+y=0

y=8

If A+B+6=0

3A+2*(-A-6)=0

3A-2A-12=0

A=12

B=-6-12=-18

Then from (1)144-72+y=0

y=-72

Thus y=8 or -72

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