Question

a and b are zeros of p(x)=3x^2-x-4 then 1/a+1/b is​

Answer 1

p(x)=3x^2 -x-4

=1/a +1/b= b+a /ab

= ( sum of zeroes) /( product of zeros)

= -b/a / c/a

=-b/a * a/c

= -b/c

= -(-1)/ -4

= -1/4

Answer 2

Answer:

Step-by-step explanation:

1) As a and b are serious of the equation p(x)=0 i.e 3x^2-x-4=0

2)