Math, asked by manjotk4837, 1 year ago

A and B can compete a piece of work in 18 days. They worked together for 12 days and then A left. B alone finished the work in 15 days. If Rs. 1500 be paid for the work then A's share is:
A.Rs. 750
B.Rs. 800
C.Rs. 600
D.Rs. 900

Answers

Answered by SmãrtyMohït
16
Here is the solution

Given :-

A and B can complete the work in 18 days:-

work rate = 100/18 = 5.55% per day.

They together can complete the work in 12
days :-

=> 5.55 × 12 = 66.66%.

Again

A leaves and B takes another 15 days to complete the whole work, Work rate of B
= 33.33/15 = 2.22% per day•

B work for (12+15) = 27 days..•

Work done by B in 27 days = 2.22×27 = 60%

40% work is done by A.

so there share should be 60% and 40% ratio.

If Rs. 1500 be paid for the work then A's share is 40% of 1500 = Rs. 600.

Hence,

C .is correct

Hope it helps you

smartyAnushka: Nice...❤
Answered by sajanchawla
0

Answer:

Step-by-step explanation:A+B=18 A+B work for 12 days. 2/3 work is complete

1 /3 remaining in 15 d

ays complete by B total work B complete 45 days

A+b complete 18 (lcm 18;45)

a=3;b=

money distribute according to efficiency A got rs ,0900ns



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