Question

A and B can complete a certain job in 20 days and 30 days respectively. They start the job together and work for 3 days. Then B falls sick and is unable to work for 5 days. During this period A works alone. After this period, B again join him and they completed the work together. In how many more days will the work be completed?​

Answer 1

Answer:

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Answer 2

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we can use LCM METHOD..

As A can complete the work in 30 day. Surely... B could complete the work in 20 days.

Step-by-step explanation:

Here, we are going to calculate LCM of 30 and 20.

The total unit of work= LCM(20,30) = 60 units

So, the number of unit work done by A = 60/30=2 units

And, the number of unit work done by B = 60/20=3 units

As per the given information, B leaves the work 5 days before the work is finished.

Therefore, A would be working alone for the last 5 days and the amount of work done by A during those days= 2*5= 10 units

Therefore, Remaining amount of work = 60-10 = 50 units

These 50 units of work is done by both A and B together.

Therefore, working together work done per day by A and B = 2+3 = 5 units

Therefore, to complete 50 units of work A and B together requires = 50/5 = 10 days

So the total number of days to finish the work = 10+5= 15 days.

Therefore ur answer is 15 dayss..

Step-by-step explanation:

hopes it's helps you :)