A and B can complete a certain work by themselves in 10 days and 12 days respectively, while C takes 20 days for the same job. A and B start working on the job together but leave after 3 days. Then C completes the remaining work. For how long did C work?
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Answer:
Given:
‘A’ complete work in 10 days and ‘B’ complete work in 12 days.
Formula used:
Time is taken = total work/efficiency to complete work
Calculation:
A can finish the work in 10 days.
∴ A’s one-day work = 1/10
Similarly B’s one day work = 1/12
∴ (A + B)’s 3 days work
⇒ (1/10 + 1/12) × 3
⇒ 11/20
Remaining work = 1 – 11/20 = 9/20
∴ time taken to finish the remaining work by B is
⇒ 9/20 ÷ 1/12
⇒ 27/5
Total time taken = 3 + 27/5
⇒ 42/5
∴ total time taken to complete work = 42/5
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