A and B can complete a job in 3 and 6 hours respectively. if they work alternatively for one hour each, with A standing the job, when will the job be completed.
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A and B can compleate a job in 3 and 6 hours respectively.if they work alternatively for 1 hour each,with A starting the job.
part of work completed on first day by A = 1/3
part of work completed on 2nd day by B = 1/6
part of work completed on 3rd day by A = 1/3
work left = 1-1/3-1/6- 1/3 = 1/6
part of work completed on 4th day by B = 1/6
so work is completed in 4 days.
2 solution
A can do a work in 3 Days so, his efficiency is =1/3;
B can do a work in 6 Days so, his efficiency is =1/6;
A and B can do the work in 2 days is (1/3+1/6) is 1/2;
so, it takes "4" to complete
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