A and B can complete a job in 4 and 5 days respectively when work separately. How many days can
they take to complete the same job, if they work together?
Answers
Step-by-step explanation:
Let A's one day work be
x
1
and B's one day work
y
1
.
It is given that A and B can complete work together in 5 days, therefore, we have:
A+B=
x
1
+
y
1
=
5
1
⇒
xy
y
+
xy
x
=
5
1
⇒
xy
y+x
=
5
1
⇒5(x+y)=xy.....(1)
A worked at twice his speed means
x
2
B worked at half of his speed means
2y
1
Together they complete work in 4 days, therefore, we have:
x
2
+
2y
1
=
4
1
⇒
2xy
4y
+
2xy
x
=
4
1
⇒
2xy
4y+x
=
4
1
⇒4(x+4y)=2xy
⇒2(x+4y)=xy
⇒2x+8y=xy.....(2)
Substitute equation 2 in 1:
5x+5y=2x+8y
⇒5x−2x=8y−5y
⇒3x=3y
⇒x=y
x=y means that number of days worked by A alone is equal to B alone.
Now, substitute the value in equation 1:
x
1
+
x
1
=
5
1
⇒
x
1+1
=
5
1
⇒
x
2
=
5
1
⇒x=5×2
⇒x=10
Hence, it would take 10 days for A alone to complete the job.
Given:
No. of days A take to complete work = 4
No. of days B take to complete work = 5
To find:
No. of days A and B take to complete work together.
Solution:
Amount of work A takes to complete in 1 day =
Amount of work B takes to complete in 1 day =
Let be the no. of days A and B take to complete the work together.
Then, amount of work both of them take to complete it together =
The total amount of work they do to complete the work together is obtained by adding the work done by A and B separately in 1 day, i.e.,
Here, the denominators are not same and hence, we cannot perform simple addition on these fractions. We take the LCM of both the denominators,i.e., and to obtain a common denominator.
A suitable number is multiplied with these denominators to obtain LCM. This suitable number is also multiplied with the numerator too.
Now, the denominators are same and thus, we can simply add them.
∴ ≈ days
Hence, A and B take 2 days to complete the job if they work together.
A and B take 2 days to complete the job if they work together.