A and B can complete a job in 8 days .Both B and C , working alone can finish the same job in 12 days. A and B commence work on job and work for 4 days whereupon A leaves. B continues for 2 more days and then leaves too. C now starts work and finishes the job.How many days does C require
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(A+B)'s 1-day work = 1/8
B's 1-day work = C's 1-day work = 1/12.
(A+B)'s 4-day work = 4x(1/8) = 1/2.
remaining work = 1 - (1/2) = 1/2
B's 2-day work = 2x(1/12) = 1/6
Remaining work = (1/2) - (1/6) = 1/3
Remaining (1/3) work is to be done by C alone whose 1-day job = (1/12)
Hence No. of days C requires = (work to be done) / (C's 1-day work)
= (1/3) / (1/12) = 4 Days
B's 1-day work = C's 1-day work = 1/12.
(A+B)'s 4-day work = 4x(1/8) = 1/2.
remaining work = 1 - (1/2) = 1/2
B's 2-day work = 2x(1/12) = 1/6
Remaining work = (1/2) - (1/6) = 1/3
Remaining (1/3) work is to be done by C alone whose 1-day job = (1/12)
Hence No. of days C requires = (work to be done) / (C's 1-day work)
= (1/3) / (1/12) = 4 Days
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..........4 days...........
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