Question

A and B Can complete a piece of work in 12 and 18 days respectively . A begins to do the work and they alternatively one at a time for one day each .the whole work will be completed in

Answer 1

Thus each of them worked for 72/10 days.

Step-by-step explanation:

Number of days taken by A and B = 12 days and 18 days

Work done by A and B  = 1/12 and 1/18

Let number of days required be = n

They alternate on it at a time for one day each. i.e. A and B each work for n/2 days.

Total work of A and B = (n /2) [(1/12)+(1/18)]

(n /2) [(1/12)+(1/18)] = 1

(n / 24) + (n / 36) =1

n = 72/5

Thus each of them worked for 72/10 days.