Question

A and B can complete a piece of work in 12 days and 18 dayes respectively. A begins to do the work and they work alternately one at a time for one day each. The whole work will be completed in?

Answer 1

A can complete a piece of work in days = 12 days
A can complete a piece of work in 1 day= 1/12
_______________________________B can complete a piece of work in days= 18 days
B can complete a piece of work in 1 day= 1/18
_______________________________
If they work together= 1/12 - 1/18
= 3/36 - 2/36
= 1/36
______________________________
work completed in days = 1 ÷ 1/36
= 1 × 36/1
= 36 days
====================================
Hope it hlps u...
Plz,.......mrk me as brainlist

Answer 2

A + B)'s 2 day's work = \( \Large \frac{1}{12}+\frac{1}{18}=\frac{5}{36} \)

(A + B)'s 14 day's work = \( \Large \frac{5}{36}\times 7 \)=\( \Large \frac{35}{36} \)

Remaining work = \( \Large  1-\frac{35}{36}=\frac{1}{36} \)

Now, it is the turn of A.

A's 1 day's work = 1/12

1/36 work is done by A in

\( \Large \left(\frac12\times{1}{36}\right) \)days= \( \Large \frac{1}{3} \)day

Total time taken = \( \Large \frac14{1}{3} \)days