Math, asked by nutron139, 1 year ago

A and b can complete a piece of work in 24 and 36 days respectively but a left 3 days before completion of the work

Answers

Answered by sibhiamar
0
A and B can complete a work in 24 days and 36 days respectively
so, A = 24 days
B = 36 days

so, total work unit = 24 + 36 = 60 units
work unit of A : B = (60/24) : (60/36)
A:B = 2.5 : 1.666

A left before 3 day of work completion so B alone work for last 3 days
so, B = 3×1.66 = 5 units

remaining work unit = 60-5 = 55 units

no of A and B can work together = (55/(2.5+1.666)) = (55/4.166) = 13.20 days

A and B work for 13.20 and B alone work for 3 days so whole work completed in 13+3 = 16 days

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