A and B can complete a piece of work in 5 days and 10 days respectively. They work together and after 2 days C joins them. The work is now completed in 1 day. In how many days can C alone do the work?
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Efficiency of A = 1/5 th part of work per day
Efficiency of B = 1/10 th part of work per day
Combined efficiency of A and B = 3/10 th part of work per day
Quantum of work done in 2 days by A and B = 3/5
Remaining work = 2/5
With the joining of C 2/5 th part of work done in 1 day
E(A + B + C) = 2/5 th part of work per day
E(A + B) = 3/10
E(C) = 1/10
Therefore C alone can do the work in 10 days.
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