A and B can complete a piece of work in 8 days and A alone completes it in 12 days. In how many days would B alone would complete the work?
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Answer:
B's one day work= 2 units/days
A's one day work =3−23−2 = 1 unit/day
4 days work of 'B' = 4×24×2 units/ days = 8 units
work left = 24−824−8 = 16 units
A will complete the remaining work in
16 units1 unit/day16 units1 unit/day= 16 days
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