Math, asked by poudyalshreya944, 9 months ago

A and B can complete a piece of work in 8 days and A alone completes it in 12 days. In how many days would B alone would complete the work?

Answers

Answered by jairanprsad
0

Answer:

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Answered by Anonymous
1

Answer:

B's one day work= 2 units/days

A's one day work =3−23−2 = 1 unit/day

4 days work of 'B' = 4×24×2 units/ days = 8 units

work left = 24−824−8 = 16 units

A will complete the remaining work in

16 units1 unit/day16 units1 unit/day= 16 days

Step-by-step explanation:

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