Question

A and b can complete a task in 25 days. B alone can compelet % of the same task in 15 days. In how many days can a alone complete of the same task?

Answer 1

A alone can alone complete 4/15th of the same task in 15 days.

Step-by-step explanation:

Hi there,

The question given above has some missing details. I have rewritten the complete question for you and solved it accordingly. Hope this is helpful. Thanks

Q. A and B can complete a task in 25 days. B alone can complete 33 (1\3)% of the same task in 15 days. In how many days can A alone complete 4/15 th of the same task?

B alone can complete 33 $\frac{1}{3}$ % of the same task in 15 days

i.e.,  33 $\frac{1}{3}$ % of task = $\frac{100}{3} * \frac{1}{100}$ = $\frac{1}{3}$rd of the task is done by B alone in 15 days

∴ The complete task will be done by B in  = $\frac{15}{\frac{1}{3}} =$ 15 × 3 = 45 days

So, In 1-day, the fraction of work done by B = $\frac{1}{45}$

A and B can together complete the task in 25 days

So, In 1-day, the fraction of work done by both A and B = $\frac{1}{25}$

Therefore,

In 1-day the fraction of work done by A is given by,

$= \frac{1}{25} - \frac{1}{45}\\=\frac{9 - 5}{225} \\= \frac{4}{225}$

Thus,

If A can alone complete the entire task in $\frac{225}{4}$ days

Then, A alone will complete $\frac{4}{15}$ of the task in = $\frac{225}{4} * \frac{4}{15}$ = 15 days

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